f(x+1)=4x^2+2x-8

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Solution for f(x+1)=4x^2+2x-8 equation:


Simplifying
f(x + 1) = 4x2 + 2x + -8

Reorder the terms:
f(1 + x) = 4x2 + 2x + -8
(1 * f + x * f) = 4x2 + 2x + -8
(1f + fx) = 4x2 + 2x + -8

Reorder the terms:
1f + fx = -8 + 2x + 4x2

Solving
1f + fx = -8 + 2x + 4x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
8 + 1f + fx + -2x + -4x2 = -8 + 2x + 4x2 + 8 + -2x + -4x2

Reorder the terms:
8 + 1f + fx + -2x + -4x2 = -8 + 8 + 2x + -2x + 4x2 + -4x2

Combine like terms: -8 + 8 = 0
8 + 1f + fx + -2x + -4x2 = 0 + 2x + -2x + 4x2 + -4x2
8 + 1f + fx + -2x + -4x2 = 2x + -2x + 4x2 + -4x2

Combine like terms: 2x + -2x = 0
8 + 1f + fx + -2x + -4x2 = 0 + 4x2 + -4x2
8 + 1f + fx + -2x + -4x2 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
8 + 1f + fx + -2x + -4x2 = 0

The solution to this equation could not be determined.

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